Re: [xsl] grouping/position problem

Subject: Re: [xsl] grouping/position problem
From: Bruce D'Arcus <bdarcus@xxxxxxxxx>
Date: Sat, 23 Apr 2005 06:10:06 -0400
On Apr 23, 2005, at 4:48 AM, Michael Kay wrote:

Assuming $NiQ is a member of current-group(), then you only need to test
"$NiQ is not the first in the group", because that implies that there is
more than one node in the group. So:


test="not($NiQ is current-group()[1])

Thanks.


But now a dumb question: how do I specify $NiQ? What the expression (or other code) that allows me to define "the member of a current-group()"? Here's the relevant bit, but I've got it wrong:

<xsl:template match="mods:modsCollection" mode="sort_author-year">
<xsl:variable name="bibrefs" select="mods:mods"/>
<xsl:for-each-group select="$bibrefs" group-by="bib:grouping-key(.)">
<xsl:sort select="current-grouping-key()"/>
<xsl:variable name="author-shorten" select="test="not(. is current-group()[1])"/>
<!-- next group -->


Bruce

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