Subject: RE: [xsl] xsl:variable with hex color values From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Fri, 20 May 2005 20:49:19 +0100 |
Another solution to add to the list you've been given: In XSLT 2.0 you can do <td bgcolor="{if (position() mod 2) then 'black' else 'white'}"> ... </td> If you want to be terse and don't mind being obscure, you can write things in XSLT 1.0 like <td bgcolor="#{substring('FFFFFF000000', (position() mod 2 * 6) + 1, 6)}"> ... </td> Michael Kay > -----Original Message----- > From: Rolando Isidoro [mailto:rli@xxxxxxxxxx] > Sent: 20 May 2005 19:34 > To: XSL Mulberrytech > Subject: [xsl] xsl:variable with hex color values > > Hi, I'm trying implementing a XSL which distinguishes odd and > even row > of a table by using different colors. My solution involves > the testing > of the number or the position, something like this: > > <xsl:choose> > <xsl:when test="position() mod 2"> > <td bgcolor = "..."> > .... > </td> > </xsl:when> > <xsl:otherwise> > <td bgcolor = "..."> > .... > </td> > </xsl:otherwise> > </xsl:choose> > > the existing code inside each of the <td>'s differs only in the > background color, which resolves into big time redundancy. Is > there any > way to assign the color value to a variable and then using it in the > bgcolor attribute? I've tried using something like <xsl:variable > name="bg" select="Black"> and then <td bgcolor = "$bg"> but > it doesn't > seem to work. I've tried with hex color values, which is my > objective, > and it didn't work either. > > Thanks, Rolando
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