RE: [xsl] xsl:variable with hex color values

["Michael Kay" <mike@xxxxxxxxxxxx>]

Another solution to add to the list you've been given: In XSLT 2.0 you can
do

<td bgcolor="{if (position() mod 2) then 'black' else 'white'}">
  ...
</td>

If you want to be terse and don't mind being obscure, you can write things
in XSLT 1.0 like

<td bgcolor="#{substring('FFFFFF000000', (position() mod 2 * 6) + 1, 6)}">
  ...
</td>

Michael Kay


> -----Original Message-----
> From: Rolando Isidoro [mailto:rli@xxxxxxxxxx] 
> Sent: 20 May 2005 19:34
> To: XSL Mulberrytech
> Subject: [xsl] xsl:variable with hex color values
> 
> Hi, I'm trying implementing a XSL which distinguishes odd and 
> even row 
> of a table by using different colors. My solution involves 
> the testing 
> of the number or the position, something like this:
> 
> <xsl:choose>
>     <xsl:when test="position() mod 2">
>        <td bgcolor = "...">
>            ....
>        </td>
>     </xsl:when>
>     <xsl:otherwise>
>        <td bgcolor = "...">
>            ....
>        </td>
>     </xsl:otherwise>
> </xsl:choose>
> 
> the existing code inside each of the <td>'s differs only in the 
> background color, which resolves into big time redundancy. Is 
> there any 
> way to assign the color value to a variable and then using it in the 
> bgcolor attribute? I've tried using something like <xsl:variable 
> name="bg" select="Black"> and then <td bgcolor = "$bg"> but 
> it doesn't 
> seem to work. I've tried with hex color values, which is my 
> objective, 
> and it didn't work either.
> 
> Thanks, Rolando