Subject: Re: [xsl] parameters in XSLT 2.0 From: David Carlisle <davidc@xxxxxxxxx> Date: Thu, 9 Jun 2005 09:43:50 +0100 |
I didn't know about sequences when I wrote it originally, and am not sure even now if I can do this: <xsl:variable name="bibrecord" as="element()+"> <xsl:sequence select="doc(concat("http://localhost:8080/exist/servlet/db/mods? ", You don't want to do that as you'll get a type error as doc() doesn't return element nodes. Also it's unnecessarily verbose as you don't need an xsLsequence you can just use select on the xsl:variable <xsl:variable name="bibrecord" select="doc(concat("http://localhost:8080/exist/servlet/db/mods? ", But if you only use this variable in one place, as input to your sorting function you don't need a variable at all, you can just inline teh expression. David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
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