Subject: RE: [xsl] Can't solve the following XSL transformation From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Mon, 25 Jul 2005 07:31:26 +0100 |
Here's a simplified form of the problem. Given this input: <chap> <para lines="3"/> <para lines="5"/> <para lines="8"/> etc </chap> produce a copy of the input, with a <page-break/> element inserted after any para that causes the cumulative number of lines to exceed 30. The answer to this is what I call "sibling recursion", something like this: <xsl:template match="chap"> <xsl:copy> <xsl:apply-templates select="para[1]"/> </xsl:copy> </xsl:template> <xsl:template match="para"> <xsl:param name="lines-so-far" select="0"/> <!-- 0 is the default value of the parameter --> <xsl:copy-of select="."/> <xsl:choose> <xsl:when test="$lines-so-far + @lines <= 30"> <xsl:apply-templates select="following-sibling::para[1]"> <xsl:with-param name="lines-so-far" select="$lines-so-far + @lines"/> </xsl:apply-templates> </xsl:when> <xsl:otherwise> <page-break/> <xsl:apply-templates select="following-sibling::para[1]"/> </xsl:otherwise> </xsl:choose> </xsl:template> Sibling recursion using xsl:apply-templates has a couple of advantages over call-template recursion: the sequence over which you are iterating is an implicit parameter (it's identified implicitly by the context node); and the recursion terminates naturally when there are no more siblings. Michael Kay http://www.saxonica.com/ > -----Original Message----- > From: John Robb [mailto:john_ok@xxxxxx] > Sent: 25 July 2005 06:22 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: Re: [xsl] Can't solve the following XSL transformation > > I'm a novice in XSLT and it's not very easy for me to realize the > second part of the algorithm.Can you please give me a short example. > Thank you in advance. > > Sun, 24 Jul 2005 23:26:09 +0100, "Michael Kay" <mike@xxxxxxxxxxxx> > PISAL(A): > > > The first stage is a classical grouping problem: see > > http://www.jenitennison.com/xslt/grouping for advice on using > >Muenchian > > grouping in XSLT 1.0, or use the new xsl:for-each-group instruction > >in 2.0. > > (Note, XSLT 1.1 doesn't really exist, it was a working draft that > >wasn't > > followed up). > > > > Insert the page breaks in a second pass through the data. This is a > >little > > tricky (I use it as an exercise on courses) and requires processing > >the > > sequence using recursion, passing a parameter in the recursive call > >that > > indicates the number of lines processed so far. > > > > Michael Kay > > http://www.saxonica.com/ > > > >> -----Original Message----- > >> From: John Robb [mailto:john_ok@xxxxxx] > >> Sent: 24 July 2005 22:45 > >> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > >> Subject: [xsl] Can't solve the following XSL transformation > >> > >> I'm a novice in XSLT and doesn't have any experience.Can > you help me > >> to perform the following transformation: > >> trasformed data should look as follows: > >> > >> **************** > >> Sector 1 > >> **************** > >> Subsector 1 > >> ++++++++++++++++ > >> ID[t]Value > >> ---------------- > >> id1[t]value1 > >> ... > >> idN valueN > >> ---------------- > >> Subsector 2 > >> ++++++++++++++++ > >> ID[t]Value > >> ---------------- > >> id1[t]value1 > >> ... > >> idN valueN > >> ... > >> **************** > >> Sector 2 > >> **************** > >> Subsector 1 > >> ++++++++++++++++ > >> ID[t]Value > >> ---------------- > >> id1[t]value1 > >> ... > >> idN valueN > >> ---------------- > >> Subsector 2 > >> ++++++++++++++++ > >> ID[t]Value > >> ---------------- > >> id1[t]value1 > >> ... > >> idN valueN > >> ... > >> > >> There is a limitation: no more than 25 data rows (idX valueX) per > >> page.Page breaks (<span style="page-break-before: always"></span>) > >> cannot be inserted in the middle of data section but before > >> sector/subsector only.I'm using XSLT v1.1. > >> Here is the xml: > >> <?xml version="1.0" encoding="iso-8859-1" ?> > >> <data> > >> [t]<item id="i1"[t]sector="s1"[t]subsector="u1">561</item> > >> [t]<item id="i10"[t]sector="s3"[t]subsector="u4">15</item> > >> [t]<item id="i22"[t]sector="s2"[t]subsector="u2">1234</item> > >> [t]<item id="i11"[t]sector="s1"[t]subsector="u2">123</item> > >> [t]<item id="i17"[t]sector="s1"[t]subsector="u3">165</item> > >> [t]<item id="i61"[t]sector="s2"[t]subsector="u1">346</item> > >> [t]<item id="i12"[t]sector="s2"[t]subsector="u5">3425</item> > >> [t]<item id="i2"[t]sector="s3"[t]subsector="u4">78</item> > >> [t]<item id="i14"[t]sector="s3"[t]subsector="u4">51</item> > >> [t]<item id="i21"[t]sector="s1"[t]subsector="u5">346</item> > >> [t]<item id="i39"[t]sector="s3"[t]subsector="u2">463</item> > >> [t]<item id="i44"[t]sector="s2"[t]subsector="u3">151</item> > >> [t]<item id="i89"[t]sector="s1"[t]subsector="u1">451</item> > >> [t]<item id="i81"[t]sector="s2"[t]subsector="u4">771</item> > >> [t]<item id="i36"[t]sector="s2"[t]subsector="u5">5654</item> > >> [t]<item id="i27"[t]sector="s3"[t]subsector="u3">362</item> > >> [t]<item id="i15"[t]sector="s1"[t]subsector="u5">234</item> > >> [t]<item id="i18"[t]sector="s3"[t]subsector="u2">73</item> > >> [t]<item id="i51"[t]sector="s3"[t]subsector="u5">567</item> > >> [t]<item id="i26"[t]sector="s1"[t]subsector="u4">17</item> > >> [t]<item id="i95"[t]sector="s3"[t]subsector="u5">67489</item> > >> [t]<item id="i13"[t]sector="s1"[t]subsector="u3">54</item> > >> [t]<item id="i71"[t]sector="s1"[t]subsector="u3">2</item> > >> [t]<item id="i23"[t]sector="s2"[t]subsector="u1">345</item> > >> [t]<item id="i7"[t]sector="s2"[t]subsector="u1">67</item> > >> [t]<item id="i80"[t]sector="s1"[t]subsector="u3">7754</item> > >> [t]<item id="i9"[t]sector="s3"[t]subsector="u4">343</item> > >> [t]<item id="i4"[t]sector="s1"[t]subsector="u2">51</item> > >> [t]<item id="i99"[t]sector="s3"[t]subsector="u5">5637</item> > >> [t][t] > >> [t][t]<sector id="s1">Sector 1</sector> > >> [t]<sector id="s2">Sector 2</sector> > >> [t]<sector id="s3">Sector 3</sector> > >> > >> [t]<subsector id="u1">Subsector 1</subsector> > >> [t]<subsector id="u2">Subsector 2</subsector> > >> [t]<subsector id="u3">Subsector 3</subsector> > >> [t]<subsector id="u4">Subsector 4</subsector> > >> [t]<subsector id="u5">Subsector 5</subsector> > >> </data>
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