RE: [xsl] Can't solve the following XSL transformation

Subject: RE: [xsl] Can't solve the following XSL transformation
From: "Michael Kay" <mike@xxxxxxxxxxxx>
Date: Mon, 25 Jul 2005 10:35:17 +0100
You just generalize the solution I gave you. Instead of using "@lines" as a
specific attribute, you have to use count(*) or something similar to count
how many child elements there are.

Michael Kay
http://www.saxonica.com/

> -----Original Message-----
> From: John Robb [mailto:john_ok@xxxxxx]
> Sent: 25 July 2005 09:13
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: Re: [xsl] Can't solve the following XSL transformation
>
> But how is it possible to determine,if the following Subsector can be
> shown on this page or on the following.The problem is how to output
> page-breaks exactly before sector/subsector only and no more than 25
> elements per pag.
>
> Mon, 25 Jul 2005 07:31:26 +0100, "Michael Kay" <mike@xxxxxxxxxxxx>
> PISAL(A):
>
> > Here's a simplified form of the problem. Given this input:
> >
> > <chap>
> >  <para lines="3"/>
> >  <para lines="5"/>
> >  <para lines="8"/>
> >  etc
> > </chap>
> >
> > produce a copy of the input, with a <page-break/> element inserted
> >after any
> > para that causes the cumulative number of lines to exceed 30.
> >
> > The answer to this is what I call "sibling recursion", something
> >like this:
> >
> > <xsl:template match="chap">
> > <xsl:copy>
> >  <xsl:apply-templates select="para[1]"/>
> > </xsl:copy>
> > </xsl:template>
> >
> > <xsl:template match="para">
> >  <xsl:param name="lines-so-far" select="0"/>  <!-- 0 is the default
> >value
> > of the parameter -->
> >  <xsl:copy-of select="."/>
> >  <xsl:choose>
> >  <xsl:when test="$lines-so-far + @lines <= 30">
> >    <xsl:apply-templates select="following-sibling::para[1]">
> >       <xsl:with-param name="lines-so-far" select="$lines-so-far +
> >@lines"/>
> >    </xsl:apply-templates>
> >  </xsl:when>
> >  <xsl:otherwise>
> >    <page-break/>
> >    <xsl:apply-templates select="following-sibling::para[1]"/>
> >  </xsl:otherwise>
> >  </xsl:choose>
> > </xsl:template>
> >
> > Sibling recursion using xsl:apply-templates has a couple of
> >advantages over
> > call-template recursion: the sequence over which you are iterating
> >is an
> > implicit parameter (it's identified implicitly by the
> context node);
> >and the
> > recursion terminates naturally when there are no more siblings.
> >
> > Michael Kay
> > http://www.saxonica.com/
> >
> >
> >> -----Original Message-----
> >> From: John Robb [mailto:john_ok@xxxxxx]
> >> Sent: 25 July 2005 06:22
> >> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> >> Subject: Re: [xsl] Can't solve the following XSL transformation
> >>
> >> I'm a novice in XSLT and it's not very easy for me to realize the
> >> second part of the algorithm.Can you please give me a
> short example.
> >> Thank you in advance.
> >>
> >> Sun, 24 Jul 2005 23:26:09 +0100, "Michael Kay" <mike@xxxxxxxxxxxx>
> >> PISAL(A):
> >>
> >> > The first stage is a classical grouping problem: see
> >> > http://www.jenitennison.com/xslt/grouping for advice on using
> >> >Muenchian
> >> > grouping in XSLT 1.0, or use the new xsl:for-each-group
> >>instruction
> >> >in 2.0.
> >> > (Note, XSLT 1.1 doesn't really exist, it was a working
> draft that
> >> >wasn't
> >> > followed up).
> >> >
> >> > Insert the page breaks in a second pass through the
> data. This is
> >>a
> >> >little
> >> > tricky (I use it as an exercise on courses) and requires
> >>processing
> >> >the
> >> > sequence using recursion, passing a parameter in the recursive
> >>call
> >> >that
> >> > indicates the number of lines processed so far.
> >> >
> >> > Michael Kay
> >> > http://www.saxonica.com/
> >> >
> >> >> -----Original Message-----
> >> >> From: John Robb [mailto:john_ok@xxxxxx]
> >> >> Sent: 24 July 2005 22:45
> >> >> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> >> >> Subject: [xsl] Can't solve the following XSL transformation
> >> >>
> >> >> I'm a novice in XSLT and doesn't have any experience.Can
> >> you help me
> >> >> to perform the following transformation:
> >> >> trasformed data should look as follows:
> >> >>
> >> >> ****************
> >> >> Sector 1
> >> >> ****************
> >> >> Subsector 1
> >> >> ++++++++++++++++
> >> >> ID[t]Value
> >> >> ----------------
> >> >> id1[t]value1
> >> >> ...
> >> >> idN valueN
> >> >> ----------------
> >> >> Subsector 2
> >> >> ++++++++++++++++
> >> >> ID[t]Value
> >> >> ----------------
> >> >> id1[t]value1
> >> >> ...
> >> >> idN valueN
> >> >> ...
> >> >> ****************
> >> >> Sector 2
> >> >> ****************
> >> >> Subsector 1
> >> >> ++++++++++++++++
> >> >> ID[t]Value
> >> >> ----------------
> >> >> id1[t]value1
> >> >> ...
> >> >> idN valueN
> >> >> ----------------
> >> >> Subsector 2
> >> >> ++++++++++++++++
> >> >> ID[t]Value
> >> >> ----------------
> >> >> id1[t]value1
> >> >> ...
> >> >> idN valueN
> >> >> ...
> >> >>
> >> >> There is a limitation: no more than 25 data rows (idX
> valueX) per
> >> >> page.Page breaks (<span style="page-break-before:
> >>always"></span>)
> >> >> cannot be inserted in the middle of data section but before
> >> >> sector/subsector only.I'm using XSLT v1.1.
> >> >> Here is the xml:
> >> >> <?xml version="1.0" encoding="iso-8859-1" ?>
> >> >> <data>
> >> >> [t]<item id="i1"[t]sector="s1"[t]subsector="u1">561</item>
> >> >> [t]<item id="i10"[t]sector="s3"[t]subsector="u4">15</item>
> >> >> [t]<item id="i22"[t]sector="s2"[t]subsector="u2">1234</item>
> >> >> [t]<item id="i11"[t]sector="s1"[t]subsector="u2">123</item>
> >> >> [t]<item id="i17"[t]sector="s1"[t]subsector="u3">165</item>
> >> >> [t]<item id="i61"[t]sector="s2"[t]subsector="u1">346</item>
> >> >> [t]<item id="i12"[t]sector="s2"[t]subsector="u5">3425</item>
> >> >> [t]<item id="i2"[t]sector="s3"[t]subsector="u4">78</item>
> >> >> [t]<item id="i14"[t]sector="s3"[t]subsector="u4">51</item>
> >> >> [t]<item id="i21"[t]sector="s1"[t]subsector="u5">346</item>
> >> >> [t]<item id="i39"[t]sector="s3"[t]subsector="u2">463</item>
> >> >> [t]<item id="i44"[t]sector="s2"[t]subsector="u3">151</item>
> >> >> [t]<item id="i89"[t]sector="s1"[t]subsector="u1">451</item>
> >> >> [t]<item id="i81"[t]sector="s2"[t]subsector="u4">771</item>
> >> >> [t]<item id="i36"[t]sector="s2"[t]subsector="u5">5654</item>
> >> >> [t]<item id="i27"[t]sector="s3"[t]subsector="u3">362</item>
> >> >> [t]<item id="i15"[t]sector="s1"[t]subsector="u5">234</item>
> >> >> [t]<item id="i18"[t]sector="s3"[t]subsector="u2">73</item>
> >> >> [t]<item id="i51"[t]sector="s3"[t]subsector="u5">567</item>
> >> >> [t]<item id="i26"[t]sector="s1"[t]subsector="u4">17</item>
> >> >> [t]<item id="i95"[t]sector="s3"[t]subsector="u5">67489</item>
> >> >> [t]<item id="i13"[t]sector="s1"[t]subsector="u3">54</item>
> >> >> [t]<item id="i71"[t]sector="s1"[t]subsector="u3">2</item>
> >> >> [t]<item id="i23"[t]sector="s2"[t]subsector="u1">345</item>
> >> >> [t]<item id="i7"[t]sector="s2"[t]subsector="u1">67</item>
> >> >> [t]<item id="i80"[t]sector="s1"[t]subsector="u3">7754</item>
> >> >> [t]<item id="i9"[t]sector="s3"[t]subsector="u4">343</item>
> >> >> [t]<item id="i4"[t]sector="s1"[t]subsector="u2">51</item>
> >> >> [t]<item id="i99"[t]sector="s3"[t]subsector="u5">5637</item>
> >> >> [t][t]
> >> >> [t][t]<sector id="s1">Sector 1</sector>
> >> >> [t]<sector id="s2">Sector 2</sector>
> >> >> [t]<sector id="s3">Sector 3</sector>
> >> >>
> >> >> [t]<subsector id="u1">Subsector 1</subsector>
> >> >> [t]<subsector id="u2">Subsector 2</subsector>
> >> >> [t]<subsector id="u3">Subsector 3</subsector>
> >> >> [t]<subsector id="u4">Subsector 4</subsector>
> >> >> [t]<subsector id="u5">Subsector 5</subsector>
> >> >> </data>
> >
>
>
>
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