Subject: Re: [xsl] concat all items in a sequence From: David Carlisle <davidc@xxxxxxxxx> Date: Wed, 31 Aug 2005 10:24:32 +0100 |
contains(string-join(for $i in elem return $i, ''), val) Is there a better way? you can (always) write for $i in elem return $i as elem so if you want to concat you could do contains(string-join(elem, ''), val) or (depending on what you want to do if val is a substring of the concatenation but not of any value, you may want true()=elem/contains(./val) David ________________________________________________________________________ This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. For more information on a proactive anti-virus service working around the clock, around the globe, visit: http://www.star.net.uk ________________________________________________________________________
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