Subject: RE: [xsl] % in xslt printing as ? From: "stuart arnold" <stuart.arnold@xxxxxxxxxxx> Date: Thu, 22 Sep 2005 18:59:16 -0400 |
I treied that, I guess I'm missing something. I'm calling at: msxsl.exe testme.xml myfix.xsl param="2005-01-01" -o out.html In the XSL, what should I have, I mean, how does it know that that param goes with what, eg <xsl:param name="Date" /> Should I have more on the command line or the XSL? Thanks for the reply and any help. -----Original Message----- From: Michael Kay [mailto:mike@xxxxxxxxxxxx] Sent: Thursday, September 22, 2005 6:38 PM To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: RE: [xsl] % in xslt printing as ? > > I'm trying to pass a variable to my xsl processor as well, but I don't > know how to recive it in the XSL. What xsl command do I use? Use <xsl:param name="nnnn"/> as a top-level element (a child of xsl:stylesheet). Then refer to the parameter just like a variable, as $nnnn. The way you actually supply the parameter a value depends on the processor API you are using. Michael Kay http://www.saxonica.com/
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