RE: [xsl] % in xslt printing as ?

["Michael Kay" <mike@xxxxxxxxxxxx>]

I don't have the msxsl documentation to hand but I would guess that if your
parameter is named Date then you specify Date="2005-01-01".

Michael Kay
http://www.saxonica.com/ 

> -----Original Message-----
> From: stuart arnold [mailto:stuart.arnold@xxxxxxxxxxx] 
> Sent: 22 September 2005 23:59
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: RE: [xsl] % in xslt printing as ?
> 
> I treied that, I guess I'm missing something.
> 
> I'm calling at:
> 	msxsl.exe testme.xml myfix.xsl param="2005-01-01" -o out.html
> 
> In the XSL, what should I have, I mean, how does it know that 
> that param
> goes with what, eg
> 	<xsl:param name="Date" />
> 
> Should I have more on the command line or the XSL?
> 
> Thanks for the reply and any help.
> 
> -----Original Message-----
> From: Michael Kay [mailto:mike@xxxxxxxxxxxx] 
> Sent: Thursday, September 22, 2005 6:38 PM
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: RE: [xsl] % in xslt printing as ?
> 
> 
> > 
> > I'm trying to pass a variable to my xsl processor as well, 
> but I don't
> 
> > know how to recive it in the XSL. What xsl command do I use?
> 
> Use <xsl:param name="nnnn"/> as a top-level element (a child of
> xsl:stylesheet). Then refer to the parameter just like a variable, as
> $nnnn. The way you actually supply the parameter a value 
> depends on the
> processor API you are using.
> 
> Michael Kay
> http://www.saxonica.com/