Re: [xsl] merging the contents of consecutive

[bryan rasmussen <rasmussen.bryan@xxxxxxxxx>]

could do that lots of different ways

how about

<xsl:template match="overview[info]">
<info><xsl:apply-templates select="info"/></info>
</xsl:template>

do whatever you want with info in an info template

your previous template should probably have been something like

<xsl:template
match="overview/info[following-sibling::*[1][local-name()='info']">
<info><xsl:value-of select="."/><xsl:text> </xsl:text><xsl:vaue-of
select="following-sibling::*[local-name()='info']"/></nfo>
</xsl:template>
and then
<xsl:template match="overview/info"/>
to get other infos out of the picture

I am however 99% certain that this is not the way you should do it ,
and instead use the other method (there is always a possiblity I don't
know some requirement you have that makes this reasonable) given this
slight hint of uncertainty I have used a rather bad xpath to get what
should have been a lot easier to get, see former example.

On 10/18/05, Annmarie Rubin (anrubin) <anrubin@xxxxxxxxx> wrote:
> Thanks for the tip, Michael.
>
> I want to generate a single element to replace two consecutive info
> elements that are children of an overview element and have the same name
> (and concatenate their contents.)  There will be no more than one pair
> of these info elements in each overview element. I don't want to
> generate a single element containing all duplicate elements.
>
> For example, this code finds the info element that is a child of an
> overview element and whose next following sibling is also an info
> element.
>
> <xsl:template match="overview/info[following-sibling::*[1][self::info]]"
> >
>
> At this point, I'm stuck. How do I concatenate both elements?
>
> thanks,
>
> Ann Marie