Subject: Re: [xsl] Problem with doctype-system in transformation xml to xml From: andrew welch <andrew.j.welch@xxxxxxxxx> Date: Wed, 7 Dec 2005 12:04:36 +0000 |
On 12/7/05, Axel Kesten <kesten@xxxxxxxxxxxxxxx> wrote: > Hi all, > > my problem is: > > I have written a stylesheet to transform a list of xml-files, given in = > an xml-config-file, to another xml-file with another structure and dtd. > Anything works fine, except of the dtd-declaration in the destination = > xml-file. > I use <xsl:output method="xml" version="1.0" encoding="UTF-8" indent="yes" > omit-xml-declaration="no" doctype-system="C:\A.dtd" media-type="text/xml" /> > > to create the dtd-declaration. > In the A.dtd the first element is A, but the result in the destination = > xml-file is as follows: > <!DOCTYPE B SYSTEM "C:\A.dtd"> > > and B is exactly the second element in the destination xml-file and it = > is the only element, defined in the A.dtd as content for A. > > Of course this xml-file is not valid. If i change manually to <!DOCTYPE = > A SYSTEM "C:\A.dtd"> it's valid. That means, all the other code should = > be OK. > > What is the problem? Can anybody give me a hint what I'm doing wrong? > > I'm using XML-Version 1.0, XSL 2.0 and altovaxml-processor 2006 (with = > Altova XSLT 2.0 Engine) to create the output file. For this to happen <B> must be the root element of your output, eg: <xsl:template match="/"> <B> ... You need to post a small complete example stylesheet that causes this problem so it can be recreated, eg <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:output omit-xml-declaration="no" doctype-system="C:\A.dtd"/> <xsl:template match="/"> <B></B> </xsl:template> </xsl:stylesheet> cheers andrew
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