Subject: Re: [xsl] Finding the position of an ancestor From: Kamal Bhatt <kbhatt@xxxxxxxxx> Date: Tue, 20 Dec 2005 13:53:51 +1100 |
<xsl:template match="Step"> <xsl:apply-templates select="descendant::Chunk[@type='FieldRef']"> <xsl:with-param name="pos" select="position()"/> </xsl:apply-templates>
<xsl:emplate match="Chunk"> <xsl:param name="pos"/> <!-- Field processing goes here --> </xsl:template>
I was wondering if someone can help me work out a position issue I'm struggling with.
I've got some XML that has is in it :
<FMPReport>
<File>
<ScriptCatalog>
<Script>
<StepList>
<Step>
...
</Step>
<Step>
...
</Step>
<Step>
...
</Step>
<Step id="1" name="Perform Script" enable="True">
<Value>
<DisplayCalculation>
<Chunk type="FieldRef">
<Field id="32867" name="cPref Server Temp Folder" table="gPrefs" />
Then in the xslt I run a for each loop
<xsl:for-each select="/FMPReport/File/ descendant::Chunk[@type='FieldRef']/Field">
<xsl:call-template name="RESULTSET" />
</xsl:for-each>
which works fine, and I can get the data I need. I grab the name from the Step using :
<xsl:value-of select="ancestor::Step[1]/@name" />
But how do I grab the step number? For example I want to know that this is step 4 in this script, by counting how many <Step> elements there are in the current <Script> element. I thought it would just be :
<xsl:value-of select="ancestor::Step[1]/position ()"/>
But that doesn't work, and gives me a parsing error. Am I maybe going about the whole thing wrong?
Thanks, Nick
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