[xsl] Finding the position of an ancestor

[Nicholas Orr <nick@xxxxxxxxxxx>]

I was wondering if someone can help me work out a position issue I'm  
struggling with.

I've got some XML that has is in it :

<FMPReport>
    <File>
        <ScriptCatalog>
            <Script>
                <StepList>
                    <Step>
                       ...
                    </Step>
                    <Step>
                       ...
                    </Step>
                    <Step>
                       ...
                    </Step>
                    <Step id="1" name="Perform Script" enable="True">
                       <Value>
                            <DisplayCalculation>
                               <Chunk type="FieldRef">
                                    <Field id="32867" name="cPref  
Server Temp Folder" table="gPrefs" />

Then in the xslt I run a for each loop

                <xsl:for-each select="/FMPReport/File/ 
descendant::Chunk[@type='FieldRef']/Field">
                    <xsl:call-template name="RESULTSET" />
                </xsl:for-each>

which works fine, and I can get the data I need.  I grab the name  
from the Step using :

                    <xsl:value-of select="ancestor::Step[1]/@name" />

But how do I grab the step number?  For example I want to know that  
this is step 4 in this script, by counting how many <Step> elements  
there are in the current <Script> element.  I thought it would just be :

                   <xsl:value-of select="ancestor::Step[1]/position 
()"/>

But that doesn't work, and gives me a parsing error.  Am I maybe  
going about the whole thing wrong?

Thanks,
Nick