RE: [xsl] Returning an element's position number

["Cindy Hunt" <Cindy.Hunt@xxxxxxx>]

Thanks so much - that did the trick!

Cindy Hunt


-----Original Message-----
From: David Carlisle [mailto:davidc@xxxxxxxxx]
Sent: Thursday, February 16, 2006 10:21 AM
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Subject: Re: [xsl] Returning an element's position number


see the recent thread (with the rather unhelpful tile "Re: [xsl] Stumped on
XPath")

  The trick with doing cross references in XSLT is always generate the
  reference text _at the referenced node_ not on the referencing node.
  then you can easily get the same number in the reference and in the
  referenced heading. (Often by just calling a named template or special
  mode that just does the numbering.


so just have
<xsl:key name="l" match="legend" use="@id"/> then on your reference element do
<xsl:for-each select="key('l',@link)">
                         <xsl:number/>
</xsl:for-each<

so that you generate the number on the <legend element even though it is
output at the point of the reference.

David

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