[xsl] get the parent of the node returned by current() funcion.

Subject: [xsl] get the parent of the node returned by current() funcion.
From: Jagsmiles <jagsmiles@xxxxxxxxx>
Date: Sun, 14 May 2006 11:26:22 +0200
xsl has current() function which returns the current node.

does it has something like parent() which returns the parent of the
node returned by current() funcion.

I have to use within a select expression of <xsl:sort> element.,
I have to get the information of current()' parent within the context
of other node.
i tried using .. , parent::* , but they are behaving with reference to
the other node, and not with reference to the node returned by
current() node.


Thanks, Jagsmiles.

Current Thread