Re: [xsl] get the parent of the node returned by current() funcion.

Subject: Re: [xsl] get the parent of the node returned by current() funcion.
From: Jagsmiles <jagsmiles@xxxxxxxxx>
Date: Sun, 14 May 2006 18:47:11 +0200
thanks very much. it really worked, now i can traverse to any of the
node relative to current() node.

Greetings,
Jagsmiles.

On 5/14/06, George Cristian Bina <george@xxxxxxxxxxxxx> wrote:
Hi,

Use current()/parent::node()

Best Regards,
George
---------------------------------------------------------------------
George Cristian Bina
<oXygen/> XML Editor, Schema Editor and XSLT Editor/Debugger
http://www.oxygenxml.com


Jagsmiles wrote: > xsl has current() function which returns the current node. > > does it has something like parent() which returns the parent of the > node returned by current() funcion. > > I have to use within a select expression of <xsl:sort> element., > I have to get the information of current()' parent within the context > of other node. > i tried using .. , parent::* , but they are behaving with reference to > the other node, and not with reference to the node returned by > current() node. > > > Thanks, > Jagsmiles.

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