Re: [xsl] xsl:template rules seems to be ignored

["andrew welch" <andrew.j.welch@xxxxxxxxx>]

On 5/31/06, Stefano Lampis <slampis@xxxxxxxxxxxxxxxxxxxxxx> wrote:
> I am quite new to XSL and I am trying to write a stylesheet to process a
> log file generated with Apache Logging framework.
>
> The XML file is like this
>
> === begin log.xml ===
> <?xml version="1.0" ?>
> <!DOCTYPE log4j:eventSet SYSTEM "log4j.dtd" [
>         <!ENTITY data SYSTEM "server.xml">
>         ]
> >
>
> <log4j:eventSet version="1.2"
> xmlns:log4j="http://jakarta.apache.org/log4j/";>
>         &data;
> </log4j:eventSet
> === end log.xml ===
>
> and my stylesheet is like this
>
> === begin log.xsl ===
> <?xml version="1.0" encoding="ISO-8859-1" standalone="no"?>
> <xsl:stylesheet version="1.0"
>         xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
>         xmlns:log4j="http://jakarta.apache.org/log4j";>
>
> <xsl:output method="html" />
>
> <xsl:template match="log4j:eventSet">
>         <!-- Do something here -->
> </xsl:template>
> </xsl:stylesheet>
> === end log.xsl ===
>
> But my template rules are ignored.
> Why?

You have a trailing slash on the log4j namespace in your XML

:)