Re: [xsl] xsl:template rules seems to be ignored

[Stefano Lampis <slampis@xxxxxxxxxxxxxxxxxxxxxx>]

andrew welch wrote:
> On 5/31/06, Stefano Lampis <slampis@xxxxxxxxxxxxxxxxxxxxxx> wrote:
>> I am quite new to XSL and I am trying to write a stylesheet to process a
>> log file generated with Apache Logging framework.
>>
>> The XML file is like this
>>
>> === begin log.xml ===
>> <?xml version="1.0" ?>
>> <!DOCTYPE log4j:eventSet SYSTEM "log4j.dtd" [
>>         <!ENTITY data SYSTEM "server.xml">
>>         ]
>> >
>>
>> <log4j:eventSet version="1.2"
>> xmlns:log4j="http://jakarta.apache.org/log4j/";>
>>         &data;
>> </log4j:eventSet
>> === end log.xml ===
>>
>> and my stylesheet is like this
>>
>> === begin log.xsl ===
>> <?xml version="1.0" encoding="ISO-8859-1" standalone="no"?>
>> <xsl:stylesheet version="1.0"
>>         xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
>>         xmlns:log4j="http://jakarta.apache.org/log4j";>
>>
>> <xsl:output method="html" />
>>
>> <xsl:template match="log4j:eventSet">
>>         <!-- Do something here -->
>> </xsl:template>
>> </xsl:stylesheet>
>> === end log.xsl ===
>>
>> But my template rules are ignored.
>> Why?
> 
> You have a trailing slash on the log4j namespace in your XML
> 
> :)
> 
Huge thanks, I was really going crazy

-- 
Stefano Lampis