Re: [xsl] function for getting filename

["andrew welch" <andrew.j.welch@xxxxxxxxx>]

On 9/1/06, Frank Marent <frank.marent@xxxxxxxxxxx> wrote:
> i'm struggling again and again over this point:
>
> is there a function in xslt that gives me the clean filename of the
> processed xml file? like
>
>    'myfile.xml'
>    'test.xml'
>    'anyfilename.xml'
>
> i do *not* need the document-uri. only the filename of the current
> processed xml file.

In xslt 2.0 I use:

tokenize(base-uri(.), '/')[last()]

In xslt 1.0 you'll need to pass it in as a parameter.