Subject: Re: [xsl] function for getting filename From: Colin Paul Adams <colin@xxxxxxxxxxxxxxxxxx> Date: 01 Sep 2006 12:01:18 +0100 |
>>>>> "andrew" == andrew welch <andrew.j.welch@xxxxxxxxx> writes: andrew> On 9/1/06, Frank Marent <frank.marent@xxxxxxxxxxx> wrote: >> i'm struggling again and again over this point: >> >> is there a function in xslt that gives me the clean filename of >> the processed xml file? like >> >> 'myfile.xml' 'test.xml' 'anyfilename.xml' >> >> i do *not* need the document-uri. only the filename of the >> current processed xml file. andrew> In xslt 2.0 I use: andrew> tokenize(base-uri(.), '/')[last()] That's not sound - . might not be the document node - if it's an element with an xml:base attribute in scope, then you may get something very spurious indeed. Using document-uri in your expression looks sounder. If the OP is invoking a transformation from the command line, then he can pass in the file name as a parameter. That is reliable. -- Colin Adams Preston Lancashire
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
Re: [xsl] function for getting file, andrew welch | Thread | Re: [xsl] function for getting file, andrew welch |
Re: [xsl] function for getting file, andrew welch | Date | Re: [xsl] function for getting file, Frank Marent |
Month |