Re: [xsl] Muenchian grouping with either attribute

[David Carlisle <davidc@xxxxxxxxx>]

>  I know that the standard answer in cases like this is "do the
>  Muenchian". But all the examples I've found deal with the Muenchian
>  over elements, whereas here, I need a Muenchian on the combination of
>  attr1 and attr2. 

xpath by design aims to treat attributes and elements as equally as
possible, so basically grouping attribute nodes works the same way as
grouping element nodes but you just need to add  a @  something like
this:


<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
 
 <xsl:output indent="yes"/>
 <xsl:key name="p" match="@*" use="."/>
 <xsl:key name="pn" match="@*" use="concat(name(),':',.)"/>
 
 <xsl:template match="/">
   <properties>
     <xsl:for-each select="root/item/property/@*[generate-id()=generate-id(key('p',.))]">
       <property name="{.}" >
	 <xsl:for-each select="key('p',.)[generate-id()=generate-id(key('pn',concat(name(),':',.)))]">
	   <xsl:attribute name="freq_{name()}">
	     <xsl:value-of select="count(key('pn',concat(name(),':',.)))"/>
	   </xsl:attribute>
	 </xsl:for-each>
       </property>
     </xsl:for-each>
   </properties>
 </xsl:template>
 
</xsl:stylesheet>

$ saxon prop.xml prop.xsl
<?xml version="1.0" encoding="utf-8"?>
<properties>
   <property name="foo" freq_attr1="1" freq_attr2="1"/>
   <property name="bar" freq_attr2="1" freq_attr1="2"/>
   <property name="baz" freq_attr2="1"/>
</properties>