Re: [xsl] sort by xsl:if and then sort using templates?

Subject: Re: [xsl] sort by xsl:if and then sort using templates?
From: "Max Bronsema" <max.bronsema@xxxxxxxxx>
Date: Mon, 20 Nov 2006 15:05:37 -0800
Thank you for the guidance Rashmi and David,

I seem to not be able to wrap my head around how the XSLT processor
works, I will be doing some reading and then getting back at this

Thanks again,

Max Bronsema

On 11/20/06, David Carlisle <davidc@xxxxxxxxx> wrote:

xsl:sort have to be direct children of xsl:for-each (or xsl:aply-templates) you can not nest in xsl:if (or anything else) Just put the test on your select predicate or outside the xsl:apply-templates

It's a bit hard to show exactly what you need to do as I think you over
trimmed your stylesheet, but in general rather than

<xsl:apply-templates> <xsl:if test="something"> <xsl:sort ..../> </xsl:if> </xsl:apply-templates>

do either

<xsl:apply-templates select="*[something]>


<xsl:when test="something">
<xsl:sort ..../>

depending on what you want to do if the predicate is false (no output,
or no sorting, respectively)


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	Rashmi Rubdi <dev_subscriptions@xxxxxxxxx> 	
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	 12:53 pm (2 hours ago)
Which version of XSLT/XPATH? I dont think you can compare dates with >
in XPATH1.0

You can't nest xsl:sort inside xsl:if.
xsl:if can only be nested under <xsl:apply-templates> and <xsl:for-each>

I think if you represent dates in the standard format for example:
2005-05-07T19:30:00  instead of 05/07/2005 you can simply sort dates
without having to extract the substrings of year, month and day with
reference to the code snippet you have provided.

like this:
      <xsl:sort select="date"/>

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