Re: [xsl] sort by xsl:if and then sort using templates?

Subject: Re: [xsl] sort by xsl:if and then sort using templates?
From: Rashmi Rubdi <dev_subscriptions@xxxxxxxxx>
Date: Mon, 20 Nov 2006 16:52:55 -0800 (PST)
I'm also learning XSLT and XPath, it definitely needs to be understood from
scratch even though I have background knowledge of several other programming
XSLT and XPath are quite different but very interesting.

started with these tutorials here, they give a good foundation, but they're
Practicing on smaller and simpler examples on your own also helps in
discovering and understanding it. I'm now reading few books on XSLT2.0 to
understand it properly.

But if you have any questions big or small don't
hesitate to ask here, if they are not already answered.


Original Message ----
From: Max Bronsema <max.bronsema@xxxxxxxxx>
Sent: Monday, November 20, 2006 6:05:37 PM
Subject: Re: [xsl] sort by xsl:if and then sort using templates?

Thank you
for the guidance Rashmi and David,

I seem to not be able to wrap my head
around how the XSLT processor
works, I will be doing some reading and then
getting back at this

Thanks again,

Max Bronsema

On 11/20/06,
David Carlisle <davidc@xxxxxxxxx> wrote:
> xsl:sort have to be direct
children of xsl:for-each (or
> xsl:aply-templates) you can not nest in xsl:if
(or anything else)
> Just put the test on your select predicate or outside the
> It's a bit hard to show exactly what you need to do as
I think you over
> trimmed your stylesheet, but in general rather than
> <xsl:if test="something">
> <xsl:sort ..../>
> </xsl:apply-templates>
> do either
> <xsl:apply-templates
> <xsl:sort.../>
> </xsl:sort>
> or
> <xsl:choose>
<xsl:when test="something">
> <xsl:apply-templates>
> <xsl:sort ..../>
> </xsl:when>
> <xsl:otherwise>
> </xsl:otherwise>
> depending on what you want to do
if the predicate is false (no output,
> or no sorting, respectively)
> David
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    Rashmi Rubdi <dev_subscriptions@xxxxxxxxx>     
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     12:53 pm (2 hours ago)
Which version of XSLT/XPATH? I dont
think you can compare dates with >
in XPATH1.0

You can't nest xsl:sort inside
xsl:if can only be nested under <xsl:apply-templates> and

I think if you represent dates in the standard format for
2005-05-07T19:30:00  instead of 05/07/2005 you can simply sort dates
without having to extract the substrings of year, month and day with
to the code snippet you have provided.

like this:
<xsl:sort select="date"/>
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