[xsl] Fwd: Multiple OR Expression across a node-set

Subject: [xsl] Fwd: Multiple OR Expression across a node-set
From: "Spencer Tickner" <spencertickner@xxxxxxxxx>
Date: Wed, 29 Nov 2006 11:19:20 -0800
My Sincerest apologizes, I accidentally sent this to the xml list.

Hi List,

Thanks in advance for the help. I think I left my brain in Cuba, and
cannot seem to figure out this fairly straight forward problem (well
that and secretly hoping someone has a more elegant way of doing

So I have a generated XML

 <name>Bar Archive</name>
 <name>Foo Archive</name>

Issue comes from the fact that every time I get this XML file, the
<view>s are in different, random order. I need them in a specific
order every time. Along with this, sometimes a <view> exists, and
sometimes it doesn't which should be reflected in the output. So far
my XSL looks something like this (I've marked where my if statement is

<?xml version='1.0'?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>

<xsl:template match="/">

<!-- This if statement fails (Value of expression cannot be converted
to a node-set in expression) -->
<xsl:if test="root//view/id = 'foo' | root//view/id = 'bar'">
 <p>Here are the foo bars</p>
 <xsl:apply-templates select="root//view[id='bar']"/>
 <xsl:apply-templates select="root//view[id='foo']"/>

<xsl:if test="contains(root//view/id, 'archive')">
       <p>Here are archive foo bars</p>
       <xsl:apply-templates select="root//view[id = 'bar_archive']"/>
       <xsl:apply-templates select="root//view[id = 'foo_archive']"/>



<xsl:template match="view" priority="5">
<li><xsl:value-of select="name"/></li>

<xsl:template match="view[contains(id, 'archive')]" priority="10">
<p><xsl:value-of select="name"/></p>


Any thoughts would be greatly appreciated. (PS - I am stuck with 1.0)

Thanks you,

Spencer Tickner

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