Re: [xsl] Fwd: Multiple OR Expression across a node-set

Subject: Re: [xsl] Fwd: Multiple OR Expression across a node-set
From: "Spencer Tickner" <spencertickner@xxxxxxxxx>
Date: Wed, 29 Nov 2006 15:27:21 -0800
Thank you both very much for your suggestions, I'm looking into the
lookup table now.



On 11/29/06, Wendell Piez <wapiez@xxxxxxxxxxxxxxxx> wrote:

This is a classic case for a lookup table either in your XSLT or in a
separate document (where someone else might help to maintain it :-),
accessed via the document() function.

See for some hints, or
search more broadly for "XSLT lookup tables".

The basic idea is that you construct a little XML that lists your
values; you then traverse this list instead of your input to do your
re-ordering. If you need to structure the list somehow, for example
to group the values (as your sample suggests you might), this is easy
enough to do (since it's XML). This also gives you a chance to
generate something special when values in your list are not
represented in your source file.

The code is more concise than the brute force method as well as
easier to maintain, since both your list of values and their order
are controlled as such, in one place.

I hope that helps,

At 02:19 PM 11/29/2006, you wrote:
>My Sincerest apologizes, I accidentally sent this to the xml list.
>Hi List,
>Thanks in advance for the help. I think I left my brain in Cuba, and
>cannot seem to figure out this fairly straight forward problem (well
>that and secretly hoping someone has a more elegant way of doing
>So I have a generated XML
>   <id>foo</id>
>   <name>foo</name>
>  <id>bar_archive</id>
>  <name>Bar Archive</name>
>  <id>bar</id>
>  <name>bar</name>
>  <id>foo_archive</id>
>  <name>Foo Archive</name>
>Issue comes from the fact that every time I get this XML file, the
><view>s are in different, random order. I need them in a specific
>order every time. Along with this, sometimes a <view> exists, and
>sometimes it doesn't which should be reflected in the output. So far
>my XSL looks something like this (I've marked where my if statement is
><?xml version='1.0'?>
><xsl:stylesheet version="1.0"
><xsl:template match="/">
><!-- This if statement fails (Value of expression cannot be converted
>to a node-set in expression) -->
><xsl:if test="root//view/id = 'foo' | root//view/id = 'bar'">
>  <p>Here are the foo bars</p>
>  <ul>
>  <xsl:apply-templates select="root//view[id='bar']"/>
>  <xsl:apply-templates select="root//view[id='foo']"/>
>  </ul>
><xsl:if test="contains(root//view/id, 'archive')">
>        <p>Here are archive foo bars</p>
>        <blockquote>
>        <xsl:apply-templates select="root//view[id = 'bar_archive']"/>
>        <xsl:apply-templates select="root//view[id = 'foo_archive']"/>
>        </blockquote>
><xsl:template match="view" priority="5">
><li><xsl:value-of select="name"/></li>
><xsl:template match="view[contains(id, 'archive')]" priority="10">
><p><xsl:value-of select="name"/></p>
>Any thoughts would be greatly appreciated. (PS - I am stuck with 1.0)
>Thanks you,
>Spencer Tickner

====================================================================== Wendell Piez mailto:wapiez@xxxxxxxxxxxxxxxx Mulberry Technologies, Inc. 17 West Jefferson Street Direct Phone: 301/315-9635 Suite 207 Phone: 301/315-9631 Rockville, MD 20850 Fax: 301/315-8285 ---------------------------------------------------------------------- Mulberry Technologies: A Consultancy Specializing in SGML and XML ======================================================================

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