Re: [xsl] Xsl:copy-of writes xmlns:xsi always - Any way to avoid this?

[Abel Braaksma <abel.online@xxxxxxxxx>]

binu.idicula@xxxxxxxxx wrote:
> I used the following .. But the problem was that it is not copying
> nested. 
> It just copies the direct chile element nodes. If the child element has
> another child, do I have to write one more for-each OR is there a simple
> way.
>
>             <xsl:for-each select="./*">
>                 <xsl:element name="{name()}"
> namespace="{namespace-uri()}">
>                 <xsl:copy-of select="@*"/>
>                 <xsl:apply-templates/>
>             </xsl:element>
>             </xsl:for-each>
>
> Once I select a particular node, all the contents (including next level
> - children) should be translated to another XML. Please advice

Michael was not talking of a for-each loop, which only walks through the 
selected node set. He meant (and gave an example of) a modified identity 
template which is the generic way of processing an input tree and modify 
only small parts of it. Use template matches instead of for-each to 
achieve that effect (see Michaels original answer).