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Subject: Re: [xsl] Key to select all same nodes(same @id) except current node From: Tech Guru <tech_gr@xxxxxxxxx> Date: Wed, 7 Mar 2007 09:48:52 -0800 (PST) |
Thanks David for your help.
I am working on XSLT 1.0.
>not sure what you mean
by top element. If you mean ancestor then in 2
>that's
>key('ParentKey',@id)
intersect ancestor::category
By saying top element, I mean all ancestors of
the current element.
Could you please tell me what the above syntax would be
in XSLT 1.0.
- R
----- Original Message ----
From: David Carlisle
<davidc@xxxxxxxxx>
To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
Sent: Wednesday, March
7, 2007 12:40:19 PM
Subject: Re: [xsl] Key to select all same nodes(same @id)
except current node
best to say of you want xslt1 or 2.
in 2
key('ParentKey',@id) except .
will return all category elements with the
current id except the current
node.
in 1 you'd write it as
key('ParentKey',@id)[not(generate-id()=generate-id(current()))]
> Also I want
to check whether any <category> elements
> with same @id, exists in all top
elements of current
> <category> element.
not sure what you mean by top
element. If you mean ancestor then in 2
that's
key('ParentKey',@id)
intersect ancestor::category
David
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