Re: [xsl] &

Subject: Re: [xsl] &
From: Marco <spinmar@xxxxxxxxx>
Date: Wed, 21 Mar 2007 12:53:17 +0100
David Carlisle ha scritto:
I have a xml document with:

<NODE n="1" url="url1" visible_url="url2?escape&amp;amp;chars"></NODE>

this is almost certainly a mistake in the input and if you have control
over the generation of these files, you should fix the generator to
<NODE n="1" url="url1" visible_url="url2?escape&amp;chars"></NODE>
The problem is that I don't produce the xml but I receive it from an external source.
and it's ok;
the problem is the onmouseover attribute where I get:

disable-output-escaping is defined to do nothing in attribute values. It's almost always a bad idea to use d-o-e in any case.

you need to replace &amp; by &, in XSLT2, you could use

select="replace(@visible_url,'&amp;amp;',' &amp;')"

in XSLT1 you could use one of the many replace templates posted to this
list, or the faq to do the same transformation.
For example I can use this one:

<xsl:template name="replaceUrl">
<xsl:param name="url" />
<xsl:when test="contains($url, '&amp;amp;')">
<xsl:value-of select="concat(substring-before($url, '&amp;amp;'), '&amp;')" disable-output-escaping="yes" />
<xsl:call-template name="replacee">
<xsl:with-param name="url"><xsl:value-of select="substring-after($url, '&amp;amp;')" disable-output-escaping="yes"/></xsl:with-param>
<xsl:value-of select="$url" disable-output-escaping="yes" />

For Abel:

my javascript function (ss) on onmouseover shows the url in the status bar of browser and I have to use it.
So I'd like to find a method to solve my problem in XSL 1.0.

Best regards


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