Re: [xsl] 0x19 is not a legal XML character

Subject: Re: [xsl] 0x19 is not a legal XML character
From: Abel Braaksma <abel.online@xxxxxxxxx>
Date: Thu, 28 Jun 2007 12:21:00 +0200
Mulberry Technologies List Owner wrote:
Friends --

Unless you have an XSL-based solution to this problem please respond off list only.

I'll give that a try. Not sure this works, though, haven't tried it:


<xsl:template match="main">
<xsl:value-of select="replace(unparsed-text('offended-xml-file.xml'), '&#x19;', '')" />
</xsl:template>


Using Saxon, set it to use the XML 1.1 feature to 'on', like this:

java -jar saxon8.jar -1.1 -it main mytransform.xslt >new-output.xml

this may work and will remove all offending U+0019 chars. You must set the XML 1.1 features, because otherwise it cannot read any data (XML or otherwise) that contain non-XML 1.0 characters. The only character not allowed in XML 1.1 is U+0000.

Cheers,
-- Abel Braaksma

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