Subject: [xsl] Filling out a table row From: "Sam Carleton" <scarleton@xxxxxxxxxxxxxxxx> Date: Tue, 3 Jul 2007 20:53:54 -0400 |
I have a node set that I need to get into a table with 5 columns and how ever many rows there needs to be. I have the basic code working. The problem I have is the table is not finished when the node set is not a multiple of 5. Here is a same dataset:
<images> <image name="a">1</image> <image name="b">2</image> <image name="c">3</image> <image name="d">4</image> <image name="e">5</image> <image name="f">6</image> <image name="g">7</image> <image name="h">8</image> </images>
<xsl:template match="images"> <table border="3"> <xsl:for-each select="image[position() mod 5 = 1]"> <xsl:text> </xsl:text> <tr> <xsl:for-each select=".|following-sibling::image[position() < 5]"> <td><xsl:value-of select="concat(@name,':',.)"/></td> </xsl:for-each> </tr> </xsl:for-each> <xsl:text> </xsl:text> </table> </xsl:template>
I would simply like to finish off the table with the correct number of <td>&NBSP;</td>, now do I do that?
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