Subject: Re: [xsl] Filling out a table row From: jingjun long <longjingjun@xxxxxxxxx> Date: Wed, 04 Jul 2007 09:36:24 +0800 |
I have a node set that I need to get into a table with 5 columns and how ever many rows there needs to be. I have the basic code working. The problem I have is the table is not finished when the node set is not a multiple of 5. Here is a same dataset:
<images> <image name="a">1</image> <image name="b">2</image> <image name="c">3</image> <image name="d">4</image> <image name="e">5</image> <image name="f">6</image> <image name="g">7</image> <image name="h">8</image> </images>
And the XSLT:
<xsl:template match="images">
<table border="3">
<xsl:for-each select="image[position() mod 5 = 1]">
<xsl:text> </xsl:text>
<tr>
<xsl:for-each select=".|following-sibling::image[position() < 5]">
<td><xsl:value-of select="concat(@name,':',.)"/></td>
</xsl:for-each>
</tr>
</xsl:for-each>
<xsl:text> </xsl:text>
</table>
</xsl:template>
I would simply like to finish off the table with the correct number of <td>&NBSP;</td>, now do I do that?
Sam
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