Re: [xsl] XML with Default Namespace

["Karl Stubsjoen" <kstubs@xxxxxxxxx>]

Ok, some progress, but I can't seem to get rid of the attribute, xmlns:o.
In my identity copy, I am trying match on attribute o, like this:

	<xsl:template match="@o" mode="transform"/>

My node match looks like this:

<xsl:template match="@* | node()" mode="transform">
<xsl:copy>
<xsl:apply-templates select="@*" mode="transform"/>
<xsl:apply-templates select="node()" mode="transform"/>
</xsl:copy>
</xsl:template>

My XSL decleration includes the exclude prefix for "o", but thinking
that that is out of context, this just excludes prefixes that the xsl
document would produce, correct?  Not prefixes associated with the
source xml.

Wow!  I feel like such a beginner when it comes to namespaces!

On 8/1/07, Karl Stubsjoen <kstubs@xxxxxxxxx> wrote:
> Ok, so I do not understand what the default namespace is if I have:
>
> <Workbook xmlns="urn:schemas-microsoft-com:office:spreadsheet"
>  xmlns:o="urn:schemas-microsoft-com:office:office"
>  xmlns:x="urn:schemas-microsoft-com:office:excel"
>  xmlns:ss="urn:schemas-microsoft-com:office:spreadsheet"
>  xmlns:html="http://www.w3.org/TR/REC-html40";>
>
> ....
>
> And then, the next element under this is:
> <DocumentProperties xmlns="urn:schemas-microsoft-com:office:office">
>
> So is my xpath:
>
> select="/Workbook/DocmentProperties"
>
> Or:
>
> select="/xmlns:Workbook/xmlns:DocmentProperties"
>
> Thanks.