RE: [xsl] [XSL]Display Different Results Based on Count of NodeSets

Subject: RE: [xsl] [XSL]Display Different Results Based on Count of NodeSets
From: Alice Ju-Hsuan Wei <ajwei@xxxxxxxxxxx>
Date: Mon, 24 Sep 2007 07:17:59 -0400

This is what I got for the output (I am actually using XSLT to transform into HTML, so the XML, as described previously, was that input)

The output, oddly, when I used <xsl:value of select="count(title)"/> instead of position() it produced 2 and 1, respectively, but when the <xsl:apply-templates was inserted, it generates output of

  <div><p>Tennison, Jeni.</p>
  <p><i>Beginning XSLT</i>.</p>
   <p><i>Begining XSLT 2.0</i>.</p></div>

    <div><p>Meyer, Eric.</p>
    <p><i>The Zen of CSS</i>.</p>

When I used the one I posted earlier:

<xsl:template match="title">
          <xsl:when test="position() ='1'"/>


It brings back the same input. However, I wanted the one on the first of the <title> to be something like:

    <div><p>Tennison, Jeni. <i>Beginning XSLT</i>.</p>
        <p><i>Begining XSLT 2.0</i>.</p></div>

<div><p>Meyer, Eric. <i>The Zen of CSS.</i></p></div>

Is there some way I can do this?

Many thanks.


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