Subject: RE: [xsl] normalize-space processing all nodes hack? From: Kolací Tomáš <kolaci@xxxxxxx> Date: Fri, 2 Nov 2007 10:23:08 +0100 |
Oups, sorry guys, I have simplified my example too much :( In fact I need to apply some filtering rules on text() nodes (normalize-space(A) was there originally, but it has come out lately that some of text() nodes must be ignored). So, what I really need, is all text of A but excluding descendants of B, like: <xsl:variable name="textOnly" select="normalize-space(A//text()[not(ancestor::B)])"/> So from <A>txt1<B>txt2<C>txt3</C></B><D>txt4</D></A> I need to get "txt1txt4". Is there some "one XPath expression" way now (XSLT 1.1 + Saxon 6.5.x extensions eventually)? Thanks, Tomas > -----Original Message----- > From: Andrew Welch [mailto:andrew.j.welch@xxxxxxxxx] > Sent: Thursday, November 01, 2007 5:21 PM > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: Re: [xsl] normalize-space processing all nodes hack? > > On 01/11/2007, Kolacm Toma9 <kolaci@xxxxxxx> wrote: > > Hi! > > > > I'd like to fill variable textOnly by normalized string of all text > of the element A. I'm just wondering is there any way, I could write > it as one XPath expression, like: > > > > <xsl:variable name="textOnly" select="normalize-space(A//text())"/> > > > > (but here only the first text node is used)? > > > normalize-space(A) > > :0) > > > -- > Andrew Welch > http://andrewjwelch.com > Kernow: http://kernowforsaxon.sf.net/
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