Subject: Re: [xsl] Find the node with maximum elements From: "G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx> Date: Sat, 03 Nov 2007 15:19:45 -0400 |
I have a requirement to write a xsl transformation to find the node which has the maximum number of elements
...
The xsl should return Honda and Mitsubishi
T:\ftemp>type avaneesh.xml <Sample> <Toyota> <Car>Camry</Car> <Car>Corrola</Car> </Toyota> <Honda> <Car>Accord></Car> <Car>Civic</Car> <Car>Pilot</Car> </Honda> <Mitsubishi> <Car>Lancer</Car> <Car>Lancer</Car> <Car>Lancer</Car> </Mitsubishi> <Hyundai> <Car>Sonata</Car> <Car>Accent</Car> </Hyundai> </Sample>
T:\ftemp>type avaneesh.xsl <?xml version="1.0" encoding="US-ASCII"?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:xsd="http://www.w3.org/2001/XMLSchema" exclude-result-prefixes="xsd" version="2.0">
<xsl:template match="/"> <xsl:for-each select="/Sample/*[count(Car)=max(/Sample/*/count(Car))]"> <xsl:value-of select="name(.)"/> <xsl:text> </xsl:text> </xsl:for-each> </xsl:template>
</xsl:stylesheet> T:\ftemp>xslt2 avaneesh.xml avaneesh.xsl con Honda Mitsubishi
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