Re: [xsl] Find the node with maximum elements

["G. Ken Holman" <gkholman@xxxxxxxxxxxxxxxxxxxx>]

At 2007-11-03 12:05 -0700, Avaneesh Ramprasad wrote:
> I have a requirement to write a xsl transformation to find the node 
> which has the maximum number of elements
> ...
> The xsl should return Honda and Mitsubishi

Not sure where you are having the problem, but XSLT 2 provides the 
max() function that makes this very easy.

I hope the solution below helps.  You can optimize the speed by 
putting the max value into a variable and testing against that, but I 
just wrote the XPath as I said the requirement aloud, so this is what 
I ended up with.

. . . . . . Ken

T:\ftemp>type avaneesh.xml
<Sample>
    <Toyota>
          <Car>Camry</Car>
          <Car>Corrola</Car>
     </Toyota>
     <Honda>
            <Car>Accord></Car>
          <Car>Civic</Car>
          <Car>Pilot</Car>
     </Honda>
     <Mitsubishi>
        <Car>Lancer</Car>
        <Car>Lancer</Car>
        <Car>Lancer</Car>
     </Mitsubishi>
    <Hyundai>
        <Car>Sonata</Car>
        <Car>Accent</Car>
</Hyundai>
</Sample>

T:\ftemp>type avaneesh.xsl
<?xml version="1.0" encoding="US-ASCII"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform";
                xmlns:xsd="http://www.w3.org/2001/XMLSchema";
                exclude-result-prefixes="xsd"
                version="2.0">

<xsl:output method="text"/>

<xsl:template match="/">
  <xsl:for-each select="/Sample/*[count(Car)=max(/Sample/*/count(Car))]">
    <xsl:value-of select="name(.)"/>
    <xsl:text>
</xsl:text>
  </xsl:for-each>
</xsl:template>

</xsl:stylesheet>
T:\ftemp>xslt2 avaneesh.xml avaneesh.xsl con
Honda
Mitsubishi

T:\ftemp>

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