Subject: RE: [xsl] Find the node with maximum elements From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Sat, 3 Nov 2007 19:34:30 -0000 |
Easiest (even in 2.0) is to sort elements according to the number of children and take the last: <xsl:for-each select="Sample/*"> <xsl:sort select="count(child::*)" data-type="number"/> <xsl:if test="position()=last()"> <xsl:value-of select="name()"/> </ </ Michael Kay http://www.saxonica.com/ > -----Original Message----- > From: Avaneesh Ramprasad [mailto:avaneesh@xxxxxxxxxxxxxx] > Sent: 03 November 2007 19:05 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: [xsl] Find the node with maximum elements > > Hello, > I have a requirement to write a xsl transformation to find > the node which has the maximum number of elements > > Below is a sample xml file > > <Sample> > <Toyota> > <Car>Camry</Car> > <Car>Corrola</Car> > </Toyota> > <Honda> > <Car>Accord></Car> > <Car>Civic</Car> > <Car>Pilot</Car> > </Honda> > <Mitsubishi> > <Car>Lancer</Car> > <Car>Lancer</Car> > <Car>Lancer</Car> > </Mitsubishi> > <Hyundai> > <Car>Sonata</Car> > <Car>Accent</Car> > </Hyundai> > </Sample> > > The xsl should return Honda and Mitsubishi > > Would appreciate your help. > > Thanks > Avaneesh
Current Thread |
---|
|
<- Previous | Index | Next -> |
---|---|---|
Re: [xsl] Find the node with maximu, G. Ken Holman | Thread | Re: [xsl] Find the node with maximu, Mukul Gandhi |
Re: [xsl] Find the node with maximu, G. Ken Holman | Date | Re: [xsl] Find the node with maximu, Mukul Gandhi |
Month |