Re: [xsl] More addition questions: Using node-set()

["Dimitre Novatchev" <dnovatchev@xxxxxxxxx>]

> I guess the common part of what I'm trying to ask is, once you have a
> RTF captured in a variable, does node-set() return a newly-constructed
> node-set, or a reference to the node-set corresponding to that variable?
> It'd be nice to know. (I have an experimental alternate FXSL
> implementation that leans _heavily_ on node-set(), but I've been really
> hesitant to start using it because I have no idea how its performance
> will be compared to "pure" XSLT 1.0.)


Hi Scott,

In the quote above by "FXSL" do you mean the Functional programming
Library for XSLT (http://fxsl.sf.net) or something else?

FXSL for XSLT 1.0 does rely on the exslt:node-set() function. FXSL for
XSLT 2.0 does not use exslt:node-set() and any extension functions at
all.



-- 
Cheers,
Dimitre Novatchev
---------------------------------------
Truly great madness cannot be achieved without significant intelligence.
---------------------------------------
To invent, you need a good imagination and a pile of junk
-------------------------------------
You've achieved success in your field when you don't know whether what
you're doing is work or play



On 10/11/07, Scott Trenda <Scott.Trenda@xxxxxxxx> wrote:
> I had thought that node-set() was a trivial operation before, but the
> Mozilla devs keep barking about how it's non-trivial and difficult to
> hack into Transformiix. It got me thinking.
>
> In XSLT 1.0, when a RTF is converted to a node-set, how are IDs and keys
> computed? Will the following be true?
>
> <xsl:variable name="rtf">
>    <node id="1"/>
>    <node id="2"/>
> </xsl:variable>
> <xsl:if test="generate-id(exsl:node-set($rtf)/node[@id=1]) =
> generate-id(exsl:node-set($rtf)/node[@id=2])">true</xsl:if>
>
> Keys... well, if your context node's document is the source document,
> there's no question, but will the key access the variable's nodes if I
> use something like this?
>    <xsl:for-each select="exsl:node-set($rtf)">
>      content
>    </xsl:for-each>
> If so, are the keys recomputed every time it's called, or only once,
> when the node-set is constructed for the first time?
>
> I guess the common part of what I'm trying to ask is, once you have a
> RTF captured in a variable, does node-set() return a newly-constructed
> node-set, or a reference to the node-set corresponding to that variable?
> It'd be nice to know. (I have an experimental alternate FXSL
> implementation that leans _heavily_ on node-set(), but I've been really
> hesitant to start using it because I have no idea how its performance
> will be compared to "pure" XSLT 1.0.)
>
> ~ Scott
>
>
> -----Original Message-----
> From: David Carlisle [mailto:davidc@xxxxxxxxx]
> Sent: Thursday, October 11, 2007 9:44 AM
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: Re: [xsl] More addition questions: Using node-set()
>
>
> > and I do this 2-3 times for different problem sets in say the same
> > template,
>
> node-set in most implementations is cheap (in some  it's essentially a
> no-op) In XSLT2 the distingction between result tree fragment and node
> set goes away (and with it the need for a function)
>
> David
>
> ________________________________________________________________________
> The Numerical Algorithms Group Ltd is a company registered in England
> and Wales with company number 1249803. The registered office is:
> Wilkinson House, Jordan Hill Road, Oxford OX2 8DR, United Kingdom.
>
> This e-mail has been scanned for all viruses by Star. The service is
> powered by MessageLabs.
> ________________________________________________________________________