Subject: [xsl] first n nodes from a current-group From: "Manish_Jaiswal" <Manish_Jaiswal@xxxxxxxxxx> Date: Thu, 7 Feb 2008 18:52:47 +0530 |
Hi All, I did a transformation of a XML file.The description is given below- input XML <?xml version="1.0" encoding="ISO-8859-1"?> <School> <student rec='1'> <name>Robart J</name> </student> <student rec='2'> <name>Alex M; Peter R; Robart J</name> </student> <student rec='3'> <name>Alex M;Robart J; Dave T</name> </student> <student rec='4'> <name>Alex M;Robart J; Peter R</name> </student> </School> XSLT , I used- <School> <xsl:for-each-group select=" School/student group-by="name/tokenize(., ';\s*')"> <xsl:sort data-type="number" select="count(current-group())" order="descending" /> <xsl:sort select="current-grouping-key()"/> <xsl:for-each select="current-group()" > <xsl:if test="position()=2"> <name count="{count(current-group())}"> <xsl:value-of select="current-grouping-key()"/> </name> </xsl:if> </xsl:for-each> </xsl:for-each-group> </School> I m getting output like- <School> <name count='4'>Robart J</name> <name count='3'>Alex M</name> <name count='2'>Peter R</name> </School> That is all the name elements having more than or equal to 2 count value. But I wanted only the first two name elements having highest counts. that is output like: <School> <name count='4'>Robart J</name> <name count='3'>Alex M</name> </School> Please help me to do the same. Thanks in advance. Manish DISCLAIMER: This email (including any attachments) is intended for the sole use of the intended recipient/s and may contain material that is CONFIDENTIAL AND PRIVATE COMPANY INFORMATION. Any review or reliance by others or copying or distribution or forwarding of any or all of the contents in this message is STRICTLY PROHIBITED. If you are not the intended recipient, please contact the sender by email and delete all copies; your cooperation in this regard is appreciated.
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