Re: [xsl] Passing parameters using <xsl:apply-templates>

[Mark <charltonrainbird@xxxxxxxxxxxxxx>]

I'm still bashing my head against this problem. Maybe I'm making this
more complicated than necessary and don't need to use parameters,
which I still can't get to work. I think this is because I have to use
<xsl:apply-templates to set the value of my parameter and I can't get
this to work when I need to use the document function. I'm not sure
whether this is fundamentally wrong or just because I can't get it to
work.

Essentially, I'm processing an xml file which is a list of xml files
using the document function:

<xsl:for-each select="document(//@filename)">

 .. processing instructions to use <xsl:for-each> and
<xsl:result-document> along with <xsl:apply-templates> to produce
split output files from each of the xml files listed in that initial
file

What I need is the document-uri(.) (which was what I was trying to do
originally) or, alternatively, as Eliot suggested, the value of
@filename to use as the prefix for my output file names.

Problem is that I just keep ending up with the value of the input file
name, not the value of the nodes attribute @filename that it
processes. Alternatively, I end up with nothing.

Any further pointers?

Thanks for your patience.

Mark


On Sat, Feb 16, 2008 at 2:16 PM, Michael Kay <mike@xxxxxxxxxxxx> wrote:
> > Another tip: a very easy-to-make and hard-to-diagnose mistake
>  > is forgetting to specify tunnel="yes" on the param statements
>
>  You can reduce the risk by getting into the habit of specifying
>  required="yes" on all parameters unless you really want them to be optional.
>
>  Michael Kay
>  http://www.saxonica.com/