Subject: Re: [xsl] Passing parameters using <xsl:apply-templates> From: Mark <charltonrainbird@xxxxxxxxxxxxxx> Date: Sat, 16 Feb 2008 19:11:04 +0000 |
I'm still bashing my head against this problem. Maybe I'm making this more complicated than necessary and don't need to use parameters, which I still can't get to work. I think this is because I have to use <xsl:apply-templates to set the value of my parameter and I can't get this to work when I need to use the document function. I'm not sure whether this is fundamentally wrong or just because I can't get it to work. Essentially, I'm processing an xml file which is a list of xml files using the document function: <xsl:for-each select="document(//@filename)"> .. processing instructions to use <xsl:for-each> and <xsl:result-document> along with <xsl:apply-templates> to produce split output files from each of the xml files listed in that initial file What I need is the document-uri(.) (which was what I was trying to do originally) or, alternatively, as Eliot suggested, the value of @filename to use as the prefix for my output file names. Problem is that I just keep ending up with the value of the input file name, not the value of the nodes attribute @filename that it processes. Alternatively, I end up with nothing. Any further pointers? Thanks for your patience. Mark On Sat, Feb 16, 2008 at 2:16 PM, Michael Kay <mike@xxxxxxxxxxxx> wrote: > > Another tip: a very easy-to-make and hard-to-diagnose mistake > > is forgetting to specify tunnel="yes" on the param statements > > You can reduce the risk by getting into the habit of specifying > required="yes" on all parameters unless you really want them to be optional. > > Michael Kay > http://www.saxonica.com/
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