Subject: [xsl] defining output document type by stylesheet parameters From: "James Sulak" <jsulak@xxxxxxxxxxxxxxxx> Date: Mon, 18 Feb 2008 11:04:24 -0600 |
Hello all, In XSLT 2.0, is it possible to define the output document type by stylesheet parameters? I've tried this without success by the following method: <xsl:stylesheet version="2.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform"> <xsl:param name="doctype.system" select="string('commbook.dtd')"/> <xsl:param name="doctype.public" select="string('-//JMP//DTD DocBook V4.4-Based Subset V0.1//EN')"/> <xsl:output method="xml" version="1.0" encoding="utf-8" doctype-system="{$doctype.system}" doctype-public="{$doctype.public}" /> I expect to get this output: <!DOCTYPE chapter PUBLIC "-//JMP//DTD DocBook V4.4-Based Subset V0.1//EN" "commbook.dtd"> But instead receive this output: <!DOCTYPE chapter PUBLIC "{$doctype.public}" "{$doctype.system}"> I know this type of thing wasn't possible in 1.0, but it seems like it might be in 2.0. Is there another approach I should be using, or am I out of luck? I'm using Saxon 9B. Thanks, -James ----- James Sulak Electronic Publishing Developer Jones McClure Publishing
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