[xsl] method transform (JAXP)

[IZASKUN GUTIERREZ GUTIERREZ <igutierrez027@xxxxxxxxxxxxx>]

Hello everybody!

I am using JAXP to execute templates.In the method transformer.transform , the

second parameter is one StreamResult. I can obtain the result in a File like

this:


File output = new File  
("C:/Users/Izaskun/Desktop/workspace5/modelo/mayo.txt");
transformer.transform(new StreamSource(sourceId), new StreamResult(output));


I need to obtain the result in a var String because the result is only  
one line

 and I dont know how to do it, because I tried a lot of forms but I  
dont obtain

this.

Could anybody help me?

Regards,

Izaskun