Re: [xsl] method transform (JAXP)

["Mukul Gandhi" <gandhi.mukul@xxxxxxxxx>]

After quickly looking at the Java APIs, following comes to my mind:

StringWriter sw = new StringWriter();
StreamResult sr = new StreamResult(sw);
transformer.transform(new StreamSource(sourceId), sr);
StringBuffer sb = sr.getBuffer();

This has not been tested.

On 5/8/08, IZASKUN GUTIERREZ GUTIERREZ <igutierrez027@xxxxxxxxxxxxx> wrote:
> Hello everybody!
>
> I am using JAXP to execute templates.In the method transformer.transform ,
> the
>
> second parameter is one StreamResult. I can obtain the result in a File like
>
> this:
>
>
> File output = new File
> ("C:/Users/Izaskun/Desktop/workspace5/modelo/mayo.txt");
> transformer.transform(new StreamSource(sourceId), new StreamResult(output));
>
>
> I need to obtain the result in a var String because the result is only one
> line
>
>  and I dont know how to do it, because I tried a lot of forms but I dont
> obtain
>
> this.
>
> Could anybody help me?
>
> Regards,
>
> Izaskun


-- 
Regards,
Mukul Gandhi