Subject: Re: [xsl] xsl:sort with XSLT 2.0 translated to XSLT 1.0 From: "Andrew Welch" <andrew.j.welch@xxxxxxxxx> Date: Thu, 19 Jun 2008 14:30:55 +0100 |
2008/6/19 Martin Honnen <Martin.Honnen@xxxxxx>: > > Assuming 'foo' elements can have a 'bar' and a 'baz' attribute and you want to process them sorted on @bar if present, otherwise on @baz then the following XSLT 2.0 > > <xsl:apply-templates select="foo"> > <xsl:sort select="(@bar, @baz)[1]"/> > </xsl:apply-templates> > > does that nicely I think. > > How would you translate that to XSLT 1.0? I can only think of a temporary tree (created with a node-set extension function) where you create a new attribute merging the two attributes first, then process the temporary tree sorted on the new attribute. > What's wrong with: (@bar | @baz)[1] ? -- Andrew Welch http://andrewjwelch.com Kernow: http://kernowforsaxon.sf.net/
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