RE: [xsl] create xml from incoming xml and load it into a variable

["Michael Kay" <mike@xxxxxxxxxxxx>]

Well, you can't use xsl:key anywhere other other than as a child of
xsl:stylesheet.

How to correct your code depends rather on what you thought your code was
intended to mean. I suspect you want the xsl:key as written, but moved to
the right place, and a call on the key() function where you currently have
the xsl:key element.

Remember that an xsl:key declaration is not tied to a specific document or
tree. It's the call on key() that determines which tree will be searched.

Michael Kay
http://www.saxonica.com/ 

> -----Original Message-----
> From: sudheshna iyer [mailto:sudheshnaiyer@xxxxxxxxx] 
> Sent: 25 July 2008 21:37
> To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> Subject: Re: [xsl] create xml from incoming xml and load it 
> into a variable
> 
> Thank you.
> 
> I did this using:
> 	<xsl:template match="root">
> 	  <xsl:variable name="var">
> 	    <xsl:element name="subroot" use-attribute-sets="id">
> 		<xsl:apply-templates select="bbb"/>
> 	    </xsl:element>
> 	  </xsl:variable>
> 	  
> 	  <!--Traverse the variable-->
> 	  <xsl:for-each select="xalan:nodeset($var)/root/subroot">
> 	    <xsl:key name="ccc" match="subroot" use="11"/> ===> 
> ERROR!!!!
> 	  </xsl:for-each>
> 	</xsl:template>
> 
> Sample xml:
> <?xml version="1.0" encoding="UTF-8"?>
> <root>    
>     <subroot id="11111">
>         <ccc>11</ccc>
>         <ddd>2005-08-26</ddd>
>         <eee>aaaaaaaa</eee>
>     </subroot>
>     <subroot id="11111">
>         <ccc>22</ccc>
>         <ddd>2005-08-26</ddd>
>         <eee>aaaaaaaa</eee>
>     </subroot>
>     <subroot id="11111">
>         <ccc>11</ccc>
>         <ddd>2005-08-26</ddd>
>         <eee>aaaaaaaa</eee>
>     </subroot>
> </root> 
> 
> Inside the loop, I need to use  <xsl:key name="ccc" 
> match="subroot" use="ccc"/>. 
> But while transforming, I am receiving the following error:
> 
> xsl:key is not allowed in this position in the stylesheet!
> 
> How do I use "key" tag inside a variable which contains xml?
> 
> I appreciate your help.
> 
> 
> --- On Fri, 7/25/08, Andrew Welch <andrew.j.welch@xxxxxxxxx> wrote:
> 
> > From: Andrew Welch <andrew.j.welch@xxxxxxxxx>
> > Subject: Re: [xsl] create xml from incoming xml and load it into a 
> > variable
> > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx
> > Date: Friday, July 25, 2008, 6:02 AM
> > 2008/7/25 sudheshna iyer <sudheshnaiyer@xxxxxxxxx>:
> > > How do I create xml from incoming xml and load it into
> > a variable from xsl? Afterr loading I
> > >
> > > have to loop through the variable for doing more xsl
> > transformations?
> > >
> > > My xsl has incoming xml. I have to create another xml
> > of different format, put it in a variable
> > > and loop through that variable to apply more xsl
> > transformations.
> > 
> > 
> > Do the first pass in a variable:
> > 
> > <xsl:variable name="first-pass">
> >   <xsl:apply-templates mode="first-pass"/> </xsl:variable>
> > 
> > The do the second pass by calling apply-templates on the first pass:
> > 
> > <xsl:apply-templates select="$first-pass"/>
> > 
> > ...or something similar - you may want to mode the second 
> pass if it's 
> > less work.  Remember to have two root match templates, one 
> moded, to 
> > ensure do don't get infinite recursion.
> > 
> > If the first pass could be a one-off batch process, then 
> you're better 
> > off separating out the transforms than repeatedly doing the 
> first pass 
> > each time.
> > 
> > --
> > Andrew Welch
> > http://andrewjwelch.com
> > Kernow: http://kernowforsaxon.sf.net/