Re: [xsl] relative URI in href

[Rolf Schumacher <mailinglist@xxxxxxxxx>]

Ok, Florent that makes sense, however xsl:include still works yet by the
following code with absolut href. The included xslt resides in the same
dir as the bill.xsl.

        String path =
eu.ngong.bill.Bill.class.getResource("bill.xsl").getPath();
        this.xslt = new StreamSource(new File(path));
        this.xslt.setSystemId(path);
            TransformerFactory tFactory = TransformerFactory.newInstance();
            Transformer transformer = tFactory.newTransformer(this.xslt);
            transformer.transform(srcXml, fo);

Do you spot something wrong here?

regards, Rolf


Florent Georges wrote:
> Vladimir Nesterovsky wrote:
>
>   Hi
>
>   
>> if source refer to a file system you better create it as
>>     
>
>   
>>       source = new StreamSource(new File(stylesheet));
>> or 
>>       source = new StreamSource(stylesheet);
>>     
>
>   Or if the stylesheet is got from a byte stream or a SAX events
> stream, simply use Source.setSystemId.
>
>   The idea is that in order to resolve URIs, the processor has to know
> where the stylesheet is.  If it is got from a File or a URI, it can
> know that info, but not otherwise, so you would have to help it.
>
>   Regards,
>
> --drkm
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