Re: [xsl] relative URI in href

[Rolf Schumacher <mailinglist@xxxxxxxxx>]

-revised 2-
Ok, Florent that makes sense, however, it works only by an absolute path
like

<xsl:include href="/p/package/includee.xsl"/>

while

<xsl:include href="includee.xsl"/> leads to the error message

Had IO Exception with stylesheet file: includee.xsl

includee.xsl resides in the same dir /p/package as the includer.xsl.

String path=package.Main.class.getResource("includer.xsl").getPath();
Source xslt = new StreamSource(new File(path));
xslt.setSystemId(path);
Transformer transformer =
  TransformerFactory.newInstance().newTransformer(xslt);
transformer.transform(srcXml, fo);

Do you spot something wrong here?

regards, Rolf


Florent Georges wrote:
> Vladimir Nesterovsky wrote:
>
>   Hi
>
>   
>> if source refer to a file system you better create it as
>>     
>
>   
>>       source = new StreamSource(new File(stylesheet));
>> or 
>>       source = new StreamSource(stylesheet);
>>     
>
>   Or if the stylesheet is got from a byte stream or a SAX events
> stream, simply use Source.setSystemId.
>
>   The idea is that in order to resolve URIs, the processor has to know
> where the stylesheet is.  If it is got from a File or a URI, it can
> know that info, but not otherwise, so you would have to help it.
>
>   Regards,
>
> --drkm
>
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