Subject: [xsl] populate nodelist variable with a variable in select statement|
From: Lara Brian <lara_bc@xxxxxxxxx>
Date: Mon, 1 Dec 2008 15:45:15 -0800 (PST)
Hi, I am trying to populate a variable with a nodelist that takes a variable in its select statement. For example, <xsl:variable name="myNodeSet" select="site/assets/asset[(type/@code = 'aaa') and starts-with(@vpath,'my/path/') and (lang='us_en') and $SEARCH_STRING]"/> and SEARCH_STRING is defined as <xsl:param name="SEARCH_STRING"> and ( (related/@code = '111') or (related/@code = '222') or (related/@code = '333') )</xsl:param> My xml is of the form, <site> <assets> <asset vpath="my/path/and/more"> <lang>eng</lang> <featured-item>No</featured-item> <type code="aaa"/> <related code="111"/> <related code="777"/> </asset> <asset> ... </asset> </assets> <site> Is this even possible? I can do this using <xsl choose> and checking each condition and setting the variable accordingly, but in future if i have more conditions for the variable, i need to add more conditions in all my xsls. It would be nice if i can set this variable in one place and then use it use it as a replace string. Thanks for any help or pointers in this regard.