Subject: RE: [xsl] populate nodelist variable with a variable in select statement From: "Michael Kay" <mike@xxxxxxxxxxxx> Date: Mon, 1 Dec 2008 23:50:57 -0000 |
Variables hold values, not fragments of path expressions. There's no facility in standard XSLT to construct an XPath expression from a string at run-time, which is what you are trying to do. However, many processors have an extension to do this, generally called xx:evaluate() or similar. Michael Kay http://www.saxonica.com/ > -----Original Message----- > From: Lara Brian [mailto:lara_bc@xxxxxxxxx] > Sent: 01 December 2008 23:45 > To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx > Subject: [xsl] populate nodelist variable with a variable in > select statement > > Hi, > I am trying to populate a variable with a nodelist that takes > a variable in its select statement. > > For example, > <xsl:variable name="myNodeSet" > select="site/assets/asset[(type/@code = 'aaa') and > starts-with(@vpath,'my/path/') and (lang='us_en') and > $SEARCH_STRING]"/> > > and SEARCH_STRING is defined as > <xsl:param > name="SEARCH_STRING"> and ( (related/@code = '111') or > (related/@code = '222') or (related/@code = '333') )</xsl:param> > > My xml is of the form, > <site> > <assets> > <asset vpath="my/path/and/more"> > <lang>eng</lang> > <featured-item>No</featured-item> > <type code="aaa"/> > <related code="111"/> > <related code="777"/> > </asset> > <asset> > ... > </asset> > </assets> > <site> > > Is > this even possible? I can do this using <xsl choose> and > checking each condition and setting the variable accordingly, > but in future if i have more conditions for the variable, i > need to add more conditions in all my xsls. It would be nice > if i can set this variable in one place and then use it use > it as a replace string. > > Thanks for any help or pointers in this regard.
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