Subject: Re: [xsl] xsl:for-each-group and identity transform From: David Carlisle <davidc@xxxxxxxxx> Date: Fri, 23 Jan 2009 12:19:38 GMT |
> Am I right that it is not possible to skip xsl:copy-of and use the > identity template instead. you can use any xslt construct that you like. If you apply-templates to current-group() and that fires an identity template then why not? David ________________________________________________________________________ The Numerical Algorithms Group Ltd is a company registered in England and Wales with company number 1249803. The registered office is: Wilkinson House, Jordan Hill Road, Oxford OX2 8DR, United Kingdom. This e-mail has been scanned for all viruses by Star. The service is powered by MessageLabs. ________________________________________________________________________
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