Subject: RE: [xsl] Determining whether no single instance of a specific node exists From: "Mtekel" <thx@xxxxxxxxx> Date: Thu, 4 Jun 2009 20:51:54 +0200 |
Hello, <xsl: if test="not(exists( (b/c) ) )" > ... </xsl:if> Check other functions here: http://www.w3schools.com/xpath/xpath_functions.asp#sequence You can use all xpath functions in the if/when test condition. m. -----Original Message----- From: Mark Peters [mailto:markpeters.work@xxxxxxxxx] Sent: 4. jzna 2009 20:21 To: xsl-list@xxxxxxxxxxxxxxxxxxxxxx Subject: [xsl] Determining whether no single instance of a specific node exists Hi Everyone, I have the following XML document: <a> <b/> <b/> <b/> </a> <a> <b/> <b/> <b> <c/> </b> </a> <a> <b/> <b/> <b/> </a> For each <b/> set, I want to apply a transformation only if no single instance of <c/> exists. I know how to check whether a node does exist, but not how to check whether no single instance of the node exists. I've tried the following conditional statements without success: 1, <xsl:when test="not(a/b/c)"> 2. <xsl:when test="count(not(a/b/c)) >= 1"> What conditional statement should I use? Thanks in advance for any help. Mark
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