Re: [xsl] Want to print elements/attrib specified by an XPath that is passed as a param

[Liam Quin <liam@xxxxxx>]

On Mon, Jun 15, 2009 at 08:04:48PM -0700, John Christopher wrote:
> My goal: I want an XSLT stylesheet that displays the contents
> of any element or attribute whose name I pass to the stylesheet
> as an XPath via a param.

[...]

There are three main approaches I can think of here.

(1) write an XSLT stylesheet that generates a new stylesheet in
which those XPath fragments (or template match patterns) are
in fact hard-coded...

(2) use the eval extension in an implementation that provides it

(3) interpret the XPath expression in XSLT.

E.g.
<xsl:template match="*">
  <xsl:param name="name" />

  <xsl:if test="localname() = $name">
     <xsl:message>got one!</xsl:message>
  </xsl:if>
  <xsl:apply-templates />
</xsl:template>

Well, this doesn't handle a/b, but you could use substring-after
to handle that, or, in XSLT 2, you could split the string on "/"
and then look for predicates, and you could do fancy things with count()
to sort into document rder & weed out duplicates.

But I'd favour approach (1) probably.

Liam

-- 
Liam Quin, W3C XML Activity Lead, http://www.w3.org/People/Quin/
http://www.holoweb.net/~liam/ * http://www.fromoldbooks.org/